Question

Solve this simultaneous equation using elimination method ​

Answer 1

$\Large{\bf{\green{\mathfrak{\dag{\underline{\underline{Given:-}}}}}}}$

• 2x + y = 5 and 2x + 3y = 3

$\Large{\bf{\orange{\mathfrak{\dag{\underline{\underline{To \: Find:-}}}}}}}$

• Values of x and y.

$\Large{\bf{\red{\mathfrak{\dag{\underline{\underline{Solution:-}}}}}}}$

First,

• 2x + y = 5 $\longrightarrow \boxed{1}$

• 2x + 3y = 3 $\longrightarrow \boxed{2}$

$\boxed{2} \: - \: \boxed{1}$ ,

• 2x + 3y = 3

• - (2x + y = 5)

Solving,

• 2x + 3y = 3

• - 2x - y = - 5

————————————

• 2y = - 2

• y = $\sf \dfrac{- \: 2}{2}$

• y = - 1

Now,

Substituting y = - 1 in $\boxed{1}$ ,

• 2x + y = 5

• 2x - 1 = 5

• 2x = 5 + 1

• 2x = 6

• x = $\sf \dfrac{6}{2}$

• x = 3.

Therefore,

• $\boxed{\purple{\textsf{x = 3 and y = -1}}}$