solve this simultaneous equation using substitution method plz 2x+3y=3 6x-12y=-5
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2x+3y=3------eq i
x= 3-3y/2------eq ii
6x-12y=-5-----eq iii
put the value of x from eq i in eq iii
6(3-3y)/2-12y=-5
3(3-3y)-12y=-5
9-9y-12y=-5
-21y= -5-9
-21y= -14
y= -14/-21
y= 2/3
put the value of y in eq ii
x= 3-3×2/3
______ = 3-2/2
2
x= 1/2
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