solve this simultaneous linear equations , take(x+2y)=a and (3x-2y)=b then solve
follow me and get more points
Attachments:
Answers
Answered by
0
Step-by-step explanation:
Your required answer is here
Take 1/(x+2y)=a and 1/(3x-2y)=b
So equation would be
a/2 + 5b/3 = -3/2
5a/4 + 3b/5 = 61/60
Multiply 1st eqaution by 6 and second by 60
3a + 10b = -9
75a + 48b = 61
Multiply 1 equ by 25
75a + 250b = -225
- 75a -. 48b = - 61
_________________
0a + 202b = - 268
b = -268/202
Answered by
1
Answer:
Mera bhi ICSE board hai.
Similar questions