Question

solve this simultaneous linear equations , take(x+2y)=a and (3x-2y)=b then solve

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Answer 1

Step-by-step explanation:

Your required answer is here

Take 1/(x+2y)=a and 1/(3x-2y)=b

So equation would be

a/2 + 5b/3 = -3/2

5a/4 + 3b/5 = 61/60

Multiply 1st eqaution by 6 and second by 60

3a + 10b = -9

75a + 48b = 61

Multiply 1 equ by 25

75a + 250b = -225

- 75a -. 48b = - 61

_________________

0a + 202b = - 268

b = -268/202

Answer 2

Answer:

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