Question

SOLVE THIS.
sin$\theta$=? ,cos=$\theta$=?, tan$\theta$=1/√3.​

Answer 1

Answer:

tan theta =1/√3

tan theta =tan30

Neglecting tan both sides.

theta =30

sin theta = sin 30 =1/2

cos theta = cos 30 =√3/2

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Answer 2

Answer:

Tan theta = perpendicular /base

=

$1 \div \sqrt{3}$

So P = 1 and B = 3^-2

By pythagorous theoram

H^2 = P^2 + B^2

so

$h = \sqrt{1 + 3}$

H = 2

sin theta = P/H

= 1/2

cos theta = B/H

$\sqrt{3 } \div 2$

Hope it helps..

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