Question

solve this solve this solve this..... questions (iii) and (ii)​

Answer 1

Answer:

(ii) 4y - 2 = 18

4y = 18 +2

4y = 20

y = 20/4

y = 5

Step-by-step explanation:

(iii) 3m/2 -3 = 4

3m/2 = 4+3

3m/2 = 7

3m = 7 ×2

3m = 14

m = 14/3

Answer 2

Solve the Following Equations by the Trial and Error Method:

(i) $\bold {x + 4 = 12}$

$\begin {aligned} \bold {x + 4 = 12} & \Rightarrow x = 12 - 4\\\\& \Rightarrow \bold {x = 8} \end {aligned}$

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(ii) $\bold {4y - 2 = 18}$

$\begin {aligned} \bold {4y - 2 = 18} & \Rightarrow 4y = 18 + 2\\\\& \Rightarrow 4y = 20\\\\\therefore \bold y & = \frac{20}{4} = \bold 5 \end {aligned}$

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(iii) $\bold {\frac{3m}{2} - 3 = 4}$

$\begin {aligned} \bold {\frac{3m}{2} - 3 = 4} & \Rightarrow \frac{3m}{2} = 7\\\\& \Rightarrow 3m = 7 \times 2\\\\& \Rightarrow \bold {3m = 14}\\\\\therefore \: \bold m & = \bold {\frac{14}{3}} \end {aligned}$

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(iv) $\bold {5y + 8 = 3y - 4}$

$\begin {aligned} \bold {5y + 8 = 3y - 4} & \Rightarrow 5y - 3y = (-4) - 8\\\\& \Rightarrow \bold {2y = (-12)}\\\\\therefore \: \bold y & = \frac{-(12)}{2} = \bold {(-6)} \end {aligned}$

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