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answer is 10
when we rationalise a we get 5-2√6
on rationalising 1/a we get 5+2√6
adding both we get 10
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when we rationalise a we get 5-2√6
on rationalising 1/a we get 5+2√6
adding both we get 10
please follow me
vicky54270p5vwfs:
how 5- root 6??
Answered by
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Answer:
Step-by-step explanation:
It's b) = 10
Hi there ......
First u have to rationalize a = √3 - √2 /√3 + √2
=√3 - √2 × ( √3 - √2 ) / √3 + √2 × (√3 - √2)
=(√3 - √2)^2 / (√3)^2 - (√2)^2
= (√3)^2 - 2×√3 ×√2 + (√2)^2 / 1
= 3 -2√6 + 2 / 1
= 5 -2√6
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a = 5 - 2√6
Now , a + 1/a = a^2 + 1 / a
Putting a = 5 - 2√6......
( 5 - 2√6) ^2 + 1 / (5 - 2√6)
After opening the bracket using (a- b)^2
= 25 - 20√6 + 24 + 1 / (5 - 2√6)
= (50 - 20√6 ) × ( 5 + 2√6) / (5 - 2√6) × ( 5 + 2√6)
= 250 + 100√6 - 100√6 - 240 / 5^2 - (2√6)^2
= 10 / 1
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Therefore ans = 10
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