Math, asked by brainlybrain8, 1 year ago

solve this step by step explanation needed ​

Attachments:

Answers

Answered by s280012
9

Answer:

C.   A loss of 2.25%

Step-by-step explanation:

Let the costs of the two televisions be A and B.

1955 is a 15% gain on the first TV

=> 1955 = 1.15 A

=> A = 1955 / 1.15

1955 is a 15% loss on the second TV

=> 1955 = 0.85 B

=> B = 1955 / 0.85

The total cost of the two TVs was

C = A+B = 1955 ( 1/1.15 + 1/0.85 )

The total selling price of the two TVs was

S = 2 × 1955

So...

S/C = 2 / ( 1/1.15 + 1/0.85 )              [ this is the harmonic mean! ]

     = 0.9775

So there was a loss of

1-0.9775

= 0.0225

= 2.25 %


s280012: Hello. Hope this is helpful. Plz mark it brainliest if you get the chance. Have a good day!
Answered by Sauron
11

\textbf{\underline{\underline{Answer :-}}}

\boxed{\boxed{\tt{Option.c}}}

\boxed{\boxed{\tt{Loss\% \:  \:  \: 2 \dfrac{1}{4}\%}}}

\textbf{\underline{\underline{Explanation :-}}}

Given :

Televisions = 2

Selling price of each TV = Rs.1955

Gain of = 15% on one

Loss of = 15 % on another

To find :

The gain or loss % in the whole transaction.

Solution :

For first Television :

S.P = Rs. 1995

Gain % = 15 %

As we known,

\tt{\implies\:CP =  \left(\dfrac{100}{100 +Gain\%}\right) \times SP}

\tt{\implies \: CP =  \left(\dfrac{100}{100 + 15}\right) \times 1955}

\tt{\implies \: CP = \dfrac{100}{115} \times 1955}

\tt{\implies \: CP =  \dfrac{195500}{115} }

\tt{\implies \: CP = 1700}

{\boxed{\bigstar{\sf\:{Cost\:Price\: of\:one\:TV = Rs.1700}}}}

For the second Television :

S.P = Rs.1955

Loss % = 15 %

As we know =

\tt{\implies\:CP =  \left(\dfrac{100}{100  - loss\%}\right) \times SP}

\tt{\implies\:CP =  \left(\dfrac{100}{100  - 15}\right) \times 1955}

\tt{\implies\:CP = \dfrac{100}{85} \times 1955}

\tt{\implies\:CP = \dfrac{195500}{85}}

\tt{\implies\:CP =2300}

{\boxed{\bigstar{\sf\:{Cost\:Price of\: second\:TV = Rs.2300}}}}

Now, total CP =

\tt{\implies1700 + 2300}

\tt{\implies4000}

{\boxed{\bigstar{\sf\:{Total\:Cost\: Price\:= Rs.4000}}}}

Total S.P =

\tt{\implies1995 \times 2}

\tt{\implies3910}

{\boxed{\bigstar{\sf\:{Total\:Selling\: Price\:= Rs.3910}}}}

Loss =

\tt{\implies \: CP  - SP}

\tt{\implies4000 - 3910}

\tt{\implies90}

{\boxed{\bigstar{\sf\:{Loss= Rs.90}}}}

Loss % =

\tt{\implies \:  \dfrac{loss}{cp} \times 100 }

\tt{\implies \dfrac{90}{4000} \times 100}

\tt{\implies \dfrac{9}{4}\%}

\tt{\implies2 \dfrac{1}{4}\%}

\boxed{\boxed{\tt{2 \dfrac{1}{4}\%}}}

Therefore the answer is

\boxed{\boxed{\tt{Option.c}}}

\boxed{\boxed{\tt{Loss\% \:  \:  \: 2 \dfrac{1}{4}\%}}}

Similar questions