solve this sum.........
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Given Equation is (a + b)(2a - 3b + c) - (2a - 3b) * c -------- (1)
Let's divide the equation into 2 parts in order to avoid confusion.
1st part :
= > (a + b)(2a - 3b + c)
= > a * 2a + a * -3b + a * c + 2a * b + b * -3b + b * c + 2a * b + b * -3b + b * c
= > 2a^2 - 3ab + ac + 2ab - 3b^2 + bc + 2ab - 3b^2 + bc
= > 2a^2 - ab + ac -3b^2 + bc ------- (2)
2nd part:
(2a - 3b) * c ------- (3)
Substitute (2) & (3) in (1), we get
(2a^2 - ab + ac - 3b^2 + bc) - (2a - 3b) * c
= > 2a^2 - ab + ac - 3b^2 + bc - 2ac + 3bc
= > 2a^2 - ab - ac - 3b^2 + 4bc.
Hope this helps!
Let's divide the equation into 2 parts in order to avoid confusion.
1st part :
= > (a + b)(2a - 3b + c)
= > a * 2a + a * -3b + a * c + 2a * b + b * -3b + b * c + 2a * b + b * -3b + b * c
= > 2a^2 - 3ab + ac + 2ab - 3b^2 + bc + 2ab - 3b^2 + bc
= > 2a^2 - ab + ac -3b^2 + bc ------- (2)
2nd part:
(2a - 3b) * c ------- (3)
Substitute (2) & (3) in (1), we get
(2a^2 - ab + ac - 3b^2 + bc) - (2a - 3b) * c
= > 2a^2 - ab + ac - 3b^2 + bc - 2ac + 3bc
= > 2a^2 - ab - ac - 3b^2 + 4bc.
Hope this helps!
siddhartharao77:
Thank You so much gopalachari for the brainliest.
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This is ur ans hope it will help you
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