Math, asked by gopalachari, 1 year ago

solve this sum.........

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Answered by siddhartharao77
3
Given Equation is (a + b)(2a - 3b + c) - (2a - 3b) * c   -------- (1)


Let's divide the equation into 2 parts in order to avoid confusion.


1st part :

= > (a + b)(2a - 3b + c)

= > a * 2a + a * -3b + a * c + 2a * b + b * -3b + b * c + 2a * b + b * -3b + b * c

= > 2a^2 - 3ab + ac + 2ab - 3b^2 + bc + 2ab - 3b^2 + bc

= > 2a^2 - ab + ac -3b^2 + bc    ------- (2)


2nd part:

(2a - 3b) * c   ------- (3) 


Substitute (2) & (3) in (1), we get

(2a^2 - ab + ac - 3b^2 + bc) - (2a - 3b) * c

= > 2a^2 - ab + ac - 3b^2 + bc - 2ac + 3bc

= > 2a^2 - ab - ac - 3b^2 + 4bc.



Hope this helps!

siddhartharao77: Thank You so much gopalachari for the brainliest.
Answered by tnwramit1
0
This is ur ans hope it will help you
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