solve this sum......
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given that
1/x+1 + 2/x+2 = 4/ x+4
taking LCM in left side
x+2+2(x+1)/(x+1)(x+2) = 4/x+4
x+2+2x+4/x²+2x+x +2 = 4/x+4
3x + 6 /x² +3x +2 = 4/x+4
(3x+6)(x+4) = 4(x²+3x + 2)
3x² +12x +6x +24 = 4x² +12x +8
x²-6x-16 = 0
x²-8x +2x -16= 0
x(x-8) + 2(x-8) =0
x+2 = 0 n x-8 =0
x=-2, 8
1/x+1 + 2/x+2 = 4/ x+4
taking LCM in left side
x+2+2(x+1)/(x+1)(x+2) = 4/x+4
x+2+2x+4/x²+2x+x +2 = 4/x+4
3x + 6 /x² +3x +2 = 4/x+4
(3x+6)(x+4) = 4(x²+3x + 2)
3x² +12x +6x +24 = 4x² +12x +8
x²-6x-16 = 0
x²-8x +2x -16= 0
x(x-8) + 2(x-8) =0
x+2 = 0 n x-8 =0
x=-2, 8
lucky249:
u have made a mistake in second line.....check it
yss...
I got the answer as x = 2(1 + root 3) and x = 2(1 - root 3). Is it correct?
i dont have the ans
i got 4+-root 3
srry
4+-4√3
Heheh..That's what I got.
Kindly check it.
Its okk
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