Question

Solve this sum
(3+√3) (2+√2)​

Answer 1

Step-by-step explanation:

Now, I’m going to use pythagoras, namely:

Now … we’ll extend that line with a 45° line of root 3. And that gives us a line of root 2 + root 3 length.

But how long are the sides of that root 3 triange? well …

a² + b² = c²

considering it’s a 45° triangle, a=b, and considering c equals the root of 3

a²+a² = root(3)²

2a² = 3

a² = 3/2

a = root (3/2)

So, now, considering the “full” triangle: which has a height & with 1 larger then the previous triangle:

a² + b² = c²

2a² = c²

2( 1+ root (3/2) ) ² = c²

2( 1 + 2root(3/2) + 3/2) = c²

considering 2 = root(2) ², so 2/root(2) = root (2)²/root(2) = root(2)

2( 1 + root(2)root(3) + 3/2) = c²

2( 1 + root(6) + 3/2) = c²

2 + 2root(6) + 3 = c²

answer: 5+26–√−−−−−−−√

in retrospect, we could have just done

(a−−√+b√)2=a−−√2+2a−−√b√+b√2=a+2ab−−√+b

if you square both sides

a−−√+b√=a+b+2ab−−√−−−−−−−−−−−√

Answer 2

Answer:

kkkkkkkkkkkkkk

jklkook