Question

solve this sum
3(t+2)=2(T+1)​

Answer 1

Answer:

 ${\huge{\boxed{\mathcal{\orange{ANSWER}}}}}$

Distribute

3(+2)=2(+1)

{\color{#c92786}{3(t+2)}}=2(t+1)3(t+2)=2(t+1)

3+6=2(+1

How to solve your problem

3(+2)=2(+1)

3(t+2)=2(t+1)3(t+2)=2(t+1)

Solve

1

Distribute

3(+2)=2(+1)

{\color{#c92786}{3(t+2)}}=2(t+1)3(t+2)=2(t+1)

3+6=2(+1

Answer 2

Answer: T = 1

Step-by-step explanation:  1.1     Factoring  t2-2t+1  

The first term is,  t2  its coefficient is  1 .

The middle term is,  -2t  its coefficient is  -2 .

The last term, "the constant", is  +1  

Step-1 : Multiply the coefficient of the first term by the constant   1 • 1 = 1  

Step-2 : Find two factors of  1  whose sum equals the coefficient of the middle term, which is   -2 .

     -1    +    -1    =    -2    That's it