Question

solve this sum ( anyone solve this sum I can mark as brilliant)the sum is
Divide 42 into 2 parts in such a way that ((4/5)th) of 1 part is equal to ((3/5)th)) of the other​

Answer 1

Answer- The above question is from the chapter 'Fractions'.

Question: Divide 42 into 2 parts in such a way that (4/5)th of 1st part is equal to (3/5)th of the other.

Solution: Let​ the first part be x.

So, the second part will be 42-x.

According to the question, (4/5)th of 1st part is equal to (3/5)th of the other.

This can be written as,

4/5 × x = 3/5 × (42 - x)

Multiplying by 5 both sides, we get,

4x = 3(42 - x)

4x = 126 - 3x

Transposing 3x to LHS, we get,

4x + 3x = 126

7x = 126

Dividing by 7 both sides, we get,

x = 126 ÷ 7

x = 18

So, the first part = 18

Second part = 42 - 18 = 24

∴ 18 and 24 are the required parts.

Answer 2

Answer:

Step-by-step explanation:

Let parts are x and (42 - x)

According to the question :

4/5 of x = (3/5 of(42 - x))

4x/5 = 3(42 - x)/5

4x=3 (42 - x)

4x = 126 - 3x

4x + 3x = 126

7x = 126

x= 126/7

x = 18

Parts are x = 18 and 42 - 18 = 24

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