solve this sum by unitary method
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cost of 1 egg =36/12=3
then the cost of 18= 18*3=54
second
cost of 1 ticket = 720/4=180
cost of 10 =180*10=1800
then the cost of 18= 18*3=54
second
cost of 1 ticket = 720/4=180
cost of 10 =180*10=1800
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1.
1 dozen=12 units
cost= 36rs. per dozen..
1 egg cost= 36/12= 3rs.
cost of 18 eggs= 18×3= 54 rs.
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2.
4 tickets= 720 rs.
1 ticket cost= 720/4 =180rs.
cost of 10 tickets= 180×10=1800rs.
_______________________
1.
1 dozen=12 units
cost= 36rs. per dozen..
1 egg cost= 36/12= 3rs.
cost of 18 eggs= 18×3= 54 rs.
______________________
2.
4 tickets= 720 rs.
1 ticket cost= 720/4 =180rs.
cost of 10 tickets= 180×10=1800rs.
_______________________
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