Math, asked by DHRUVBHASKAR, 1 year ago

solve this sum fast

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Answered by abhishek664
1
I hope it helps✌✌

thanks;D
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Answered by Aashi2005
1
For p(x)= kx^2-√2x+1 to be a factor of x-1,
p(1)=0. (Zero of x-1 is 1.)
k-√2+1=0
k=0+√2-1
k=√2-1
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