solve this sum please ..
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Answered by
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(3/7p2+4q2)×7(p2-3/4q2)
= (3/7p2+4q2)(7p2-21/4q2)
= 21/7p4-63/28p2q2+28q2p2-84/4q4
= 3p4-9/4p2q2+28q2p2-21q4
I hope it's help u
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= (3/7p2+4q2)(7p2-21/4q2)
= 21/7p4-63/28p2q2+28q2p2-84/4q4
= 3p4-9/4p2q2+28q2p2-21q4
I hope it's help u
Please add me in brainiest if u like this answer
komal515p8ieu8:
answer is 3p4+103/4p2q2 -21q4
Add the middle sum
it's still not coming
I tried that also
Oooo
Sorry something is mistake by me
plz solve it if possible i need the solution
I have solution
1/7(3p2+28q2)×7/4(4p2-3q2)
Solve this equation
Answered by
0
Answer:
Step-by-step explanation:
(3/7p2+4q2)×7(p2-3/4q2)
= (3/7p2+4q2)(7p2-21/4q2)
= 21/7p4-63/28p2q2+28q2p2-84/4q4
= 3p4-9/4p2q2+28q2p2-21q4
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