Question

Solve this Sum .

Question 3 Only.

[ Class 10th ] [NCERT]

Answer 1

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The 3 consecutive numbers which are in A.P are of order

⏩a- d, a , a+ d

⏩Given terms as below,

⏩2p + 1 , 13 , 5p - 3

⏩Using formula ,

➡ 2b = a + c

here, a,b,c are terms in A.P

⏩2(13) = (2p + 1 ) + ( 5p - 3)

⏩ 7p -2 = 26

⏩7p = 28

⏩p = 4

Answer is P = 4

Terms are

⏩2p + 1 = 2(4) + 1 = 9

⏩13

⏩5p -3 = 5(4) - 3 = 17

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Answer 2

Hey mate,...

Here's your answer !!,...

Solution:

Given 2p+1, 13 , 5p-3 are in AP.

To find: value of P

If a,b,c are in AP then we know that
2b=( a+c)
Here a= 2p+1
b=13
c=5p-3

2 (13) =(2p+1+5p-3)

26=7p-2

26+2=7p

28=7p

p=28/7 =4

Therefore the value of
P is 4.

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