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A and B do same work
Work =LCM (12,18)=36
Per day work of A=36/12=3
Per day work of B=36/18=2
A begin to do work and they alternatively work on each day
Work in 2 days =5
Work in 2×7=14 days=5×7=35
Work left is 1
Now its A's turn to do work
A does 3 work per day
Therefore 1 work is done by 1/3 day
Therefore total days required=14+1/3
Answer is 14 1/3 days
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