Math, asked by rajaganeshbe05, 2 days ago

solve this sum
send answer with solution

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Answered by 160336mokshithagbkm
1

A and B do same work

Work =LCM (12,18)=36

Per day work of A=36/12=3

Per day work of B=36/18=2

A begin to do work and they alternatively work on each day

Work in 2 days =5

Work in 2×7=14 days=5×7=35

Work left is 1

Now its A's turn to do work

A does 3 work per day

Therefore 1 work is done by 1/3 day

Therefore total days required=14+1/3

Answer is 14 1/3 days

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