Question

solve this take your time...ask anyone , anywhere...just solve this don't spam​... you're free to use internet...
this is a 11th class question

Answer 1

Step-by-step explanation:

we know that [ ] is a floor function

so that we have

= [x] + [ x + 1/n ] + [ x + 2/n] + ..... + [ x + (n-1)/n ]

=so that value of 1/n,2/n,..... (n-1)/n in floor function will be = 0

=> [x] + [x] + [x]+...... + n times [x]

=> [nx]

Answer 2

Answer:

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