Math, asked by cathrin12, 1 year ago

solve this
2  +  \sqrt{5 }  \div 2 -  \sqrt{5 }  = a + b \sqrt{5}
find a and b

Answers

Answered by KS199
0
2+
​2

​√
​5

​​
​​ −√
​5

​​ =a+√
​5

​​ b

2 Simplify 2+52−52+\frac{\sqrt{5}}{2}-\sqrt{5}2+
​2

​√
​5

​​
​​ −√
​5

​​ to 2−522-\frac{\sqrt{5}}{2}2−
​2

​√
​5

​​
​​
2−52=a+5b2-\frac{\sqrt{5}}{2}=a+\sqrt{5}b2−
​2

​√
​5

​​
​​ =a+√
​5

​​ b

3 Subtract 5b\sqrt{5}b√
​5

​​ b from both sides
2−52−5b=a2-\frac{\sqrt{5}}{2}-\sqrt{5}b=a2−
​2

​√
​5

​​
​​ −√
​5

​​ b=a

4 Switch sides
a=2−52−5ba=2-\frac{\sqrt{5}}{2}-\sqrt{5}ba=2−
​2

​√
​5

​​
​​ −√
​5

​​ b

cathrin12: it's too confusing
cathrin12: what's the value
Answered by anonymous64
3
Here is your answer. I hope you don't mind that bad handwriting.

Hope it'll help.. :-)
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