solve this
find a and b
Answers
Answered by
0
2+
2
√
5
−√
5
=a+√
5
b
2 Simplify 2+52−52+\frac{\sqrt{5}}{2}-\sqrt{5}2+
2
√
5
−√
5
to 2−522-\frac{\sqrt{5}}{2}2−
2
√
5
2−52=a+5b2-\frac{\sqrt{5}}{2}=a+\sqrt{5}b2−
2
√
5
=a+√
5
b
3 Subtract 5b\sqrt{5}b√
5
b from both sides
2−52−5b=a2-\frac{\sqrt{5}}{2}-\sqrt{5}b=a2−
2
√
5
−√
5
b=a
4 Switch sides
a=2−52−5ba=2-\frac{\sqrt{5}}{2}-\sqrt{5}ba=2−
2
√
5
−√
5
b
2
√
5
−√
5
=a+√
5
b
2 Simplify 2+52−52+\frac{\sqrt{5}}{2}-\sqrt{5}2+
2
√
5
−√
5
to 2−522-\frac{\sqrt{5}}{2}2−
2
√
5
2−52=a+5b2-\frac{\sqrt{5}}{2}=a+\sqrt{5}b2−
2
√
5
=a+√
5
b
3 Subtract 5b\sqrt{5}b√
5
b from both sides
2−52−5b=a2-\frac{\sqrt{5}}{2}-\sqrt{5}b=a2−
2
√
5
−√
5
b=a
4 Switch sides
a=2−52−5ba=2-\frac{\sqrt{5}}{2}-\sqrt{5}ba=2−
2
√
5
−√
5
b
cathrin12:
it's too confusing
Answered by
3
Here is your answer. I hope you don't mind that bad handwriting.
Hope it'll help.. :-)
Hope it'll help.. :-)
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