Question

solve this
$b {}^{3} + 8b{}^{2}a +16a{}^{2} b$

Answer 1

Hi ,

b³ + 8b²a + 16a²b

= b ( b² + 8ab + 16 a² )

= b [ b² + 2 × b × 4a + ( 4a )² ]

= b ( b + 4a )²

= b ( b + 4a ) ( b + 4a )

I hope this helps you.

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