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![\sqrt[16]{6} \div \sqrt[4]{2}](https://tex.z-dn.net/?f=+%5Csqrt%5B16%5D%7B6%7D++%5Cdiv++%5Csqrt%5B4%5D%7B2%7D+ "\sqrt[16]{6} \div \sqrt[4]{2}")
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,........,..................
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Answer:
I think the question typed is wrong
Step-by-step explanation:
it might be 16√6 ÷ 4√2
If so then,
√6 can also be written as √2√3
=16√2√3
4√2
= 4√3
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