Question

Solve this :-

$\sqrt{3x} - x$
Fast plzzz

Answer 1

Thanks for your suggestion!!

I'll remember this.

Here is the correction:

$\sqrt{3x}-x=c$

It can be written as

$-(\sqrt{x})^{2}+\sqrt{3}*\sqrt{x}-c=0$

By quadratic formula,

$\sqrt{x}=(-\sqrt{3}±\sqrt{3-4(1)(-c)})/2\\x=(6+4c ± 2\sqrt{3(3+4c)})/4$

where c is constant value for your given polynomial.

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Thanx!!

Note: Sorry for A in between equation. I'm unable to remove them.