Physics, asked by sharmasiddhivinayak8, 9 months ago

Solve this the first one will be brainliest

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Answered by sudeshrohtak60
1

Answer:

the water will become hot

Answered by eshalfarah123
1

Answer:

plz mark as brainliest....

Water is kept in a vessel at 30 Deg. C. a hot metal ball of temp 70 deg. C is dropped in this vessel. Now, what happens? Our observations :-

Explanation:

It is obvious that we have already studied that heat flows from body of high temperature to body of lower temperature. Here looking at the temperature difference Delta T = 70 Deg. C – 30 Deg. C.

As water is maintained at a much lower temperature as compared to Hot metal ball (which is at 70 deg. C), so the heat will flow from the Hot metal Ball towards the water.

Also when the heat flows from high temperature to lower temperature, it will continue to flow, till both bodies are at the same temperature. So, mathematically speaking this would be the average temperature between water and hot metal ball.

As the average between 70 and 30 would be = 70 + 30 / 2 = 100 / 2 = 50 Deg C.

So, it is obvious that the heat would continue to flow from hot metal ball to water till both have reached a temperature of 50 Deg. C. This means that water will have to  gain some heat from Hot metal ball, while the metal ball will have to loose some of its heat for water.

In this process of gaining and losing heat, it is also obvious that some amount of heat would be taken up by the system. Here the system is the Vessel (which will be negligible) while some heat will help change the water from its liquid for to steam.

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