Math, asked by mahek6827, 7 months ago

Solve this :

There is a certain club which is for men only. There are 600 men who belong to this club and 5% of these men wear one earring. Of the other 95% membership, half wear two earrings and the other half wear none. How many earrings are being worn in this club?

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Answers

Answered by sureshnayak19061969
2

Answer:

x = .05 * 600 = 30

y + z = .95 * 600 = 570

So far so good. Now let’s figure out how many men are split in y and z. Per the question, it’s half in y and half in z, so:

y = .5 * 570 = 285

z = .5 * 570 = 285

Now for the final equation, total number of earrings. If x is 1 earring and y is 2 we get:

1*x + 2*y + 0*z = total

Plugging in values gives us:

1*30 + 2*285 + 0*285 = 30 + 570 = 600

So we have 600 total earrings being worn in this club.

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Answered by vaibhavshinde145
1

Answer:

x = .05 * 600 = 30

y + z = .95 * 600 = 570

So far so good. Now let’s figure out how many men are split in y and z. Per the question, it’s half in y and half in z, so:

y = .5 * 570 = 285

z = .5 * 570 = 285

Now for the final equation, total number of earrings. If x is 1 earring and y is 2 we get:

1*x + 2*y + 0*z = total

Plugging in values gives us:

1*30 + 2*285 + 0*285 = 30 + 570 = 600

So we have 600 total earrings being worn in this club.

mark as brainlist

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