Question

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Answer 1

Answer:

Given :-

AB = DC and /_ABC = /_DCB.

To prove :- ∆ABC = ∆DCB.

Proof :-

In ∆ABC and ∆DCB,

Seg AB = Seg DC ..........( Given )

/_ABC. = /_DCB. ...........( Given )

Seg BC = Seg CB ...........( Common segment )

Hence ∆ABC ≈ ∆DCB .........{ By SAS test }

Answer :- Hence proved.

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