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Two radio were bought at the same cost . one was sold at alrofit of 12% and the other at a profit of 17% . if the difference in the selling price of the two radio was rs 125 what was the cost price of each radio
Answers
Answer:
2500
Step-by-step explanation:
Let the cost price of the radio be x.
(i) Profit at 12%.
Selling price of radio = x + 12% of x
= x + (12/100) * x
= (112x/100)
(ii) Profit at 17%.
Selling price of radio = x + 17% of x
= x + (17/100) * x
= (117x/100).
Given, Difference between them is 125.
⇒ (117x/100) - (112x/100) = 125
⇒ (117x - 112x)/100 = 125
⇒ (5x/100) = 125
⇒ 5x = 12500
⇒ x = 2500.
∴ Cost price of each radio = 2500.
Hope it helps!
case 1: let the c.p of the first radio be Rs 100 profit= 12% sp= 100+12 x 100 100 s.p= Rs 112 case 2: c.p of the second radio=Rs 100 p= 17% sp= 100+17 x 100 100 s.p= Rs 117 then therefore difference in s.p= Rs (117 - 112) =Rs 5 therefore,when diff. in s.p of two radios is=Rs 5 then cp=Rs 100 when diff. in s.p of the radios is= Rs 125 then cp= 100 x 125 = Rs 2500 5 therefore s.p of each radio is= Rs 2500