Question

solve this urgent h to thoda jaldi​

Answer 1

Answer :

$7(y + 3) - 2(x + 2) = 14...(1) \\ 4(y - 2) + 3(x - 3) = 2...(2) \\ \\ 7(y + 3) - 2(x + 2) = 14 \\ 7y + 21 - 2x - 4 = 14 \\ 2x + 7y = - 3 \\ 2x - y = 3 \\ 2x = 7y + 3 \\ = x = 7y + 3 \\ x = \frac{7y + 3}{2} ...(3) \\ \\ 4(y2) + 3(x - 3) = 2 \\ 4y - 8 \times + 3x - 9 = 2 \\ 3x + 4y = 19 \\ \\ = 3 \frac{(7y + 3)}{2} ) + 4y = 9 \\ \frac{21y + 9 + 8y}{2} = 19 \\ 29y + 9 = 38 \\ 29y = 29 \\ y = 1 \\ substituting \: value \: of \: y \: in \: (3) \\ x = \frac{7(1) + 3}{2} \\ \frac{10}{2} = 5$

Answer 2

Answer:

7(y+3)−2(x+2)=14...(1)

4(y−2)+3(x−3)=2...(2)

7(y+3)−2(x+2)=14

7y+21−2x−4=14

2x+7y=−3

2x−y=3

2x=7y+3

=x=7y+3

x=

2

7y+3

...(3)

4(y2)+3(x−3)=2

4y−8×+3x−9=2

3x+4y=19

=3

2

(7y+3)

)+4y=9

2

21y+9+8y

=19

29y+9=38

29y=29

y=1

substitutingvalueofyin(3)

x=

2

7(1)+3

2

10

=5