Question

solve this urgently please.....no spamming ​

Answer 1

$\huge{\pink{\underline{\mathfrak{your\:answer}}}}$

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$\bold{(C)\:5.06\:J}$

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step-by-step explanation:

We know that,

Area under F—t graph gives the impulse or the change in the linear momentum of the body. As the initial velocity and therefore the initial linear momentum of the body is zero, the area under F—t graph gives the final linear momentum of the body.

Now,

Area of ∆AOB = $\frac{1}{2}×3×4$= 6 N•s

Also,

$\frac{OA}{OB}=\frac{CD}{CB}$

=> $\frac{4}{3}=\frac{CD}{1.5}$

=> CD = 2

Therefore,

Area of ∆BCD

= - ($\frac{1}{2}× 1.5 × 2$)

= - 1.5 N•s

Therefore,

The final linear momentum = 6 - 1.5 = 4.5 N•s

Therefore,

Kinetic energy of the block

$= \frac{ {p}^{2} }{2m} = \frac{ {4.5}^{2} }{2 \times 2} = 5.06 \: joules$

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