Question

solve this urgently pls
24 and 26 pls​

Answer 1

(24)
EMF -> Voltage
Temperature -> Kelvin/Degree

E = a t + b t^2

unit of (a t) must be equal to the unit of E

unit of E = unit of a t
Volt = a (Degree)
Volt/Degree = a

Option C.

(26)

Remember this formula,

1/με = c^2
where c = speed of light.

It will be useful for JEE questions,

So dimension of 1/με is equal to the dimension of c^2

As dimension of velocity is L/T
So for c^2 dimension will be
$[{L}^{2} {T}^{ - 2}]$

Option C.

Answer 2

24. Option 'c' is correct that is volt/ degree

26. Option 'c' is correct that is [L²T⁻²]

Explanation:

• In dimensional analysis any equation is correct if dimensional formula on left hand side and right hand side are equal and the quantities having same dimensions only can show commutative properties that is can be added or subtracted from one another that is principle of homogeneity

Solution 24.

Given, E = at + b t²

where E= thermal emf

t = temperature difference

a,b = constant

Dimension of E = volt

so at and b t² must have same dimensions as of E

=> volt = a * degree

=> a = volt / degree

Hence option 'c' is correct answer

Solution 26.

• Permittivity is the resistance offered by medium to form the electric field
• Permeability is the ability of medium to allow the formation of magnetic field

Given, 1/ μ₀ξ₀

where μ₀ = magnetic permeability in free space

ξ₀ = permittivity of free space

=> 1/ μ₀ξ₀ = c²

where c = speed of light in free space

dimension of speed of light is [LT¹]

=> c² = [LT⁻¹]²

=>  1/ μ₀ξ₀ = [L²T⁻²]

Hence option 'c' is correct

To know more about dimensional analysis, visit:

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