Question

solve this using algebra laws of indices
if you solve this correctly I will mark you as brainliest ⭐​
fast fast

Answer 1

Step-by-step explanation:

(20d^-8)/5d^2×2d^-9

(20d^-8)/10d^-7

2d^-1

2÷d

9. (12k^-16×5m^-5)/(2m^-2×15k^4)

(12/2)(5/15)(k^-16/k^4)(m^-5/m^-2)

(6/3)k^-20 m^-3

2/((k^20)(m^3))

Answer 2

Given :    20d⁻⁸/(5d² * 2d⁻⁹)

24x⁻²/(3x⁻⁴*2x⁻⁷)

12k⁻¹⁶*5m⁻⁵/(2m⁻²*15k⁴)

To Find : solve this using algebra laws of indices

Solution:

$& {{\text{a}}^{n}}\times {{a}^{-n}}=1\text{ or }{{\text{a}}^{n}}=\frac{1}{{{a}^{n}}} \\ & {{a}^{m}}\times {{a}^{n}}={{a}^{m+n}} \\ & \frac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}} \\ & {{\left( {{a}^{m}} \right)}^{n}}={{\left( {{a}^{n}} \right)}^{m}}={{a}^{mn}} \\ & {{a}^{m}}\times {{b}^{m}}={{\left( ab \right)}^{m}} \\ & \frac{{{a}^{n}}}{{{b}^{n}}}={{\left( \frac{a}{b} \right)}^{n}} \\ & {{a}^{0}}=1$

20d⁻⁸/(5d² * 2d⁻⁹)

=  20d⁻⁸/(10d²⁻⁹)

=  2d⁻⁸/ d²⁻⁹

=  2d⁻⁸/ d⁻⁷

= 2d⁻⁸⁺⁷

= 2d⁻¹

= 2/d¹

= 2/d

20d⁻⁸/(5d² * 2d⁻⁹) = 2/d

Similarly :

24x⁻²/(3x⁻⁴*2x⁻⁷)

= 4x⁹

12k⁻¹⁶*5m⁻⁵/(2m⁻²*15k⁴)

= 2/(m³*k²⁰)

or

2k⁻²⁰m⁻³

Learn More:

https://brainly.in/question/35990488

0.243^0.2×10^0.6=? Pls help me it's very urgent - Brainly.in

brainly.in/question/3246219

3⁴)² ÷ [3⁴ X 3⁵] : Evaluate.

brainly.in/question/5030040