Question

Solve this using equation of motion ​

Answer 1

810 m he travels before stopping the vehicle.

It is 190 m far from the truck when it stops.

Answer 2

Answer:

Because the train will ultimately come at a stop, the value of v = 0 m/s

v = 0

u = 90

a = -5

$v^{2} - u^{2} = 2as \\0^{2} - 90^{2} = 2*-5*s \\-90^{2} = -10s \\-8100 = -10s \\\frac{-8100}{-10} = s \\810 m = s$

The train will travel a distance of 810 m before coming to a halt.

Hope it helps

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