Question

Solve this using substitution method..but please consider equation 1 first​

Answer 1

$solution \: \\ \\ 9x - 10y = - 12 \: \: .........(1) \\ \\ 2x + 3y = 13 \: \: ........(2)$

$\\ \\ from \: eq \: 1 \: \: we \: get \:$

$x \: = \frac{ - 12 + 10y}{9} \: \: ..... (3)$

$now \: substitute \: eq \: 3 \: in \: eq \: 2 \: we \: get$

$2( \frac{ - 12 + 10y}{9} ) + 3y = 13$

$(\frac{ - 24 + 20y}{9} ) + 3y = 13$

$- 24 + 20y + 27y = 117$

$47y = 117 + 24$

$47y = 141$

$y = \frac{141}{47}$

$y = 3$

$now \: substitute \: y = 3 \: in \: eq \: 2$

$x = \frac{ - 12 + 10(3)}{9}$

$x = \frac{ - 12 + 30}{9}$

$x = \frac{18}{9}$

$x = 2$

$hence \: the \: value \: of \: x = 2 \: \: and \: y = 3$

$hope \: this \: will \: help \: u$

$mark \: as \: brainliest \: answer \: please \: my \: friend$