Question

Solve this:

Velocity of light in glass is 2 × 10^8 m/s and that in air is 3 × 10^8 m/s . By how much would an ink dot appear to be raised, when covered by a glass plate 6.0 cm thick?

Answer 1

Hey there!

Answer:

Here, velocity of light in air = 3 × $10^{8}$ m/s.

Velocity of light in the glass (v) = 2 × $10^{8}$ m/s.

Therefore, refractive index of glass wrt. air,

μ = c/v

= $\dfrac{3 × 10^{8}}{2 × 10^{8}}$

= 1.5

Normal shift in the position of the ink dot,

d = $t( 1 - \dfrac{1}{u})$

Here, the thickness of the glass plate, t = 6.0 cm

Therefore,

d = $6.0 ( 1 - \dfrac{1}{1.5})$

d = $\dfrac{6.0 × 0.5}{1.5}$

d = 2.0 cm.



#Be Brainly.

Answer 2

Answer:

Here, velocity of light in air = 3 × m/s.

Velocity of light in the glass (v) = 2 × m/s.

Therefore, refractive index of glass wrt. air,

μ = c/v

=

= 1.5

Normal shift in the position of the ink dot,

d =

Here, the thickness of the glass plate, t = 6.0 cm

Therefore,

d =

d =

d = 2.0 cm.

#Be Brainly.