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Answers
Question:
A car starting from rest moves high 54 km/hr in 2 minutes. Calculate its acceleration.
Answer:
Acceleration = 0.125 m/s²
Explanation:
Given:
- Initial velocity = 0
- Final velocity = 54 km/hr
- Time = 2 minutes = 120 seconds
To find:
Acceleration = ?
Formula used:
★ a = (v - u) ÷ t
where:
- a = acceleration
- v = Final velocity
- u = Initial velocity
- t = time
Solution:
First, convert speed into m/s
54 km/hr
= 54 × 5/18
= 15 m/s
Now, apply the formula.
a = (v - u) ÷ t
⇒ a = (15 - 0) ÷ 120
⇒ a = 0.125 m/s²
∴ Acceleration of car = 0.125 m/s²
QUESTION:-
A car starting from rest moves high 54 km/hr in 2 minutes. Calculate its acceleration.
EXPLANATION:-
Initial velocity = 0 (BODY STARTS FROM REST)
Final velocity = 54 km/hr=54×5/18=15 m/s
Time = 2 minutes = 120 seconds
a = (v - u) / t
where:
a = acceleration
v = Final velocity
u = Initial velocity
t = time
So let's put the data of the question to find acceleration:-
a=(15-0)/120
a=0.125 m/s²
So the acceleration is 0.125 m/s²
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