Question

Solve this very urgent Q. No2

Answer 1

The resistors are arranged in parallel series.
Therefore, 1/net resistance =1/2+1/4+1/6
=22/24
Therefore net resistance =24/22=12/11
Here R =12/11 ohm
And I across the 3 terminals is 11 A
Therefore by ohms formula
V/I = R
V/11=12/11
V= 12 volt
The ammeter is arranged near the 2nd resistor
Therefore here
I =3A.....V/I=R
12/I = 4
Therefore I =3A
Option no 3. 12V,3A