Question

Solve this...With explanation​

Answer 1

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Answer 2

$\huge\underline{\pink{\mathbb{ANSWER :-}}}$

$\sqrt{3 + 2 \sqrt{2} }$

$= > \sqrt{ {(1 + \sqrt{2)} }^{2} }$

• by using a²+2ab+b²

$= > 1 + \sqrt{2}$

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