Question

Solve this with explanation.​

Answer 1

Answer:

kyu yr kyu acha frnd nhi bn skta ??

Answer 2

Answer:

122.5 m and 10 s

80m

Explanation:

1.

u= 49m/s

v=0m/s (since, velocity at max ht = 0m/s)

g = 9.8m/s²

by third equation of free fall,

v² = u²-2gh where h=max ht

2gh = u² since v=0

49² = 2x9.8xh

h = 2401/19.6 = 122.5 m

time taken to reach the ground = 2x time of ascent since time of ascent = time of descent

by first equation of free fall

v = u - gt where t = time of ascent

u = gt since v =0

49 = 9.8t

t = 49/9.8 = 5s

total time taken = 2x5=10s

2.

g=10m/s

u=0m/s (since velocity when dropped = 0)

t = 4s

by second equation of free fall

h = ut + 0.5gt² (where h = max ht here, ht of tower)

h = 0 + 0.5x10x 4² (since u=0, uXt =0)

h = 5x 16 = 80m

PLEASE MARK BRAINLIEST