Math, asked by AryanTennyson, 1 year ago

Solve this with process

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Answered by TheLifeRacer
3
Hey !!!

59 Q no .

=> 3√2 × 4√2 × 12√32

=> 2^1/3 × 2^1/4 × 32^1/12

=> 2^1/3 × 2^1/4 × 2^5/12

=> 2^ ( 1/3 + 1/4 + 5/12 )

=> 2^(4 + 3 + 5/12)

=> 2^12/12

=> 2¹

=> 2 Answer ✔

________________________

Hope it helps you !!!

@Rajukumar111
.

siddhartharao77: 2^1 = 2
siddhartharao77: Akk any moderators bro...
siddhartharao77: *Ask
Answered by siddhartharao77
2
Given :  \sqrt[3]{2} *  \sqrt[4]{2} *    \sqrt[12]{32}

= \ \textgreater \   2^{ \frac{1}{3} +  \frac{1}{4}  } *  \sqrt[12]{32}

= \ \textgreater \   2^{ \frac{7}{12} } *  \sqrt[12]{2^5}

= \ \textgreater \   2^{ \frac{7}{12} } *  2^{5 *  \frac{1}{12} }

 = \ \textgreater \   2^{ \frac{7}{12} +  \frac{5}{12}  }

= \ \textgreater \   2^{1}

2.


Hope this helps!
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