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Dimensions of pressure = [M][L]^1[T]^-2
Volume = [L]³
As we know that the things which have the same dimensions can only be added together.-
So, a/V² and P should have the same dimensions.
[M][L]^-1[T]^-2= a[L]^-2×3 (Since it's V² not just V)
[M][L]^-1[T]^-2= a[L]^-6
a = [M][L]^5[T]^-2
So, the answer is (A)
Volume = [L]³
As we know that the things which have the same dimensions can only be added together.-
So, a/V² and P should have the same dimensions.
[M][L]^-1[T]^-2= a[L]^-2×3 (Since it's V² not just V)
[M][L]^-1[T]^-2= a[L]^-6
a = [M][L]^5[T]^-2
So, the answer is (A)
simran25:
last step?
I didn't understand ..
what u did at last step how the power 6
come
Its V² not V, so
(L³)²
Understood ? :)
yaa thnku soo much
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