Question

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Answer 1

Answer:

${x}^{2} + \frac{1}{ {x}^{2} } = 23 \\ add \: 2 \times x \times \frac{1}{x} \: to \: both \: side \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2x \frac{1}{x} = 23 + 2x \times \frac{1}{x} \\ we \: see \: that \: {x}^{2} + \frac{1}{x {}^{2} } + 2x \times \frac{1}{x} \\ = (x + \frac{1}{x}) {}^{2} = 23 + 2 \\ {(x + \frac{1}{x}) }^{2} = 25 = {5}^{2} \\ power \: will \: be \: cancelled \\ (x + \frac{1}{x} ) = 5$

Step-by-step explanation:

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