Question

Solve this with step by step and explanation. Pls by request ​

Answer 1

Answer:

We have,

x+\dfrac{1}{x}=4 ....(1)

To find, x^2+\dfrac{1}{x^2}=?

Squaring (1) in both sides, we get

(x+\dfrac{1}{x})^{2}=4^{2}

⇒ x^2+\dfrac{1}{x^2}+2.x.\dfrac{1}{x} =16

⇒ x^2+\dfrac{1}{x^2}+2 =16

⇒x^2+\dfrac{1}{x^2}=16-2=14

∴ x^2+\dfrac{1}{x^2}=14

Hence, x^2+\dfrac{1}{x^2}=14

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Answer 2

Answer:

hlo

good morning

have a great day