solve this with substitution method :- 2x+3y=1 and 3x+2y=7
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Step-by-step explanation:
3x +2y = 8 eq 1, 2x +3y = 7 eq 2
3x = 8- 2y
x = 8-2y/3
sub x = 8-2y/3 in eq 2
2[8-2y/3] + 3y = 7
16-4y/3 + 3y = 7
Icm of 3, 1 = 3 16-4y +9y/3 = 7
16-4y+9y = 21
16 +5y = 21
5y = 21-16
5y = 5
y = 5/5
y = 1
x = 8-2y/3
x = 8-2*1/3
= 8-2/3
= 6/3
x = 2
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