Question

Solve this word problem:
Please solve in equation form and step by step explanation.

A milkman buys 10 litres of milk partly at the rate of ₹10 per litre and the remaining at the rate of ₹14 per litre. After selling the whole milk he gets ₹112. If in the transaction, he had neither gained or lost, then find the separate quantity of milk purchased at the given rates.

Please don't give wrong answers.

Answer 1

Step-by-step explanation:

He had neither gained nor loses,So he should have sold the milk in the same rate at which he brought.

Case 1:

let the litres of milk brought by him be x and y ,

the he had brought 10 litres in total,therefore,

x+y=10 ........1

Case 2:

let the capacity of milk brought by him at the rate of rupees 10 per litre be x and milk brought at the rate of rupees 12 per litre be y,then according to the question,

10x +12y=112 .........2

multiply first equation by 10,

10x+10y=100 ........3

Now,subtract equation 3 and 2 to eliminate x,

2y=12

y=6 litres

substitute y value in equation 1,

x+6=10

x=4 litres

VERIFICATION:

from equation 1 ,

4+6=10

10=10

from equation 2,

10(4)+12(6)=112

40+72=112

112=112

hence,verified

So he had brought 4 litres of milk at a cost of rupees 10 per litre, and 6 litres of milk at a cost of rupees 12 per litre.

HoPe It hELpS yoU....