Chemistry, asked by falgunichapekar, 1 year ago

Solve this worksheet please

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Answers

Answered by tony19
1
1. Δv= h/4πx me x 10^-14
After substituting the values and simplifying
Δv= 5.8 x 10^9 m/s

2. 1st orbit
Thus v= 2.18 x 10^8
c= 3 x 10^8
So 3/x= 2.18
Thus x = 1.37
So v= c/1.37

5. d) n=4 l= 1
This indicates 4p orbital which has the highest energy amongst the 4.

3. En= E1 x z^2/n^2[1/n1^2-1/n2^2]
Replacing the values n1=1 n2=2
We get En= 1.635 x10^-18
Now E= hc/λ
So λ= hc/E
λ= 19.878 x 10^-26/1.635 x10^-18
λ= 1.214 x 10^-7

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falgunichapekar: Can u answer the next question 8 had asked
tony19: Which one??
falgunichapekar: That 1 only
tony19: Which?
tony19: The one which i have solved now?
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tony19: I think i have solved question 8
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