Math, asked by joyee1938, 5 hours ago

solve this x^2-4x+4 > 0

Answers

Answered by intelligent567
1

Answer:

solve this x^2-4x+4 > 0 is

475224 {x {1y44}^{2} }^{2}

Answered by kiran12355
0

Answer:

x {}^{2}  - 4x + 4 = 0 \\  x {}^{2}  - 2x - 2x + 4 = 0 \\ x(x - 2) - 2(x - 2) = 0 \\ (x - 2)(x - 2) = 0 \\ x = 2 \:  \: or \:  \: x = 2  \:  \:  \:  \:  \: (2 > 0)

this is required solution.hope u help it.

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