Solve this
X 2 + x - 1 = 0, x = 2
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Answered by
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HEY!!
Given: x2 + x – 1 = 0 and x = 2
On substituting x = 2 in L.H.S. of the given equation, we get:
= (2)2 + 2 - 1
= 4 + 2 - 1
=5
=> L.H.S.≠R.H.S.
x = 2 does not satisfy the given equation.
Therefore, x = 2 is not a root of the given quadratic equation.
Given: x2 + x – 1 = 0 and x = 2
On substituting x = 2 in L.H.S. of the given equation, we get:
= (2)2 + 2 - 1
= 4 + 2 - 1
=5
=> L.H.S.≠R.H.S.
x = 2 does not satisfy the given equation.
Therefore, x = 2 is not a root of the given quadratic equation.
Answered by
0
x=2
2(2)+2-1=0
4+1=0
5=0
LHS is not equal to RHS
hence not verified.
i hope it helps u.^-^.
plz mark it as brain liest...
2(2)+2-1=0
4+1=0
5=0
LHS is not equal to RHS
hence not verified.
i hope it helps u.^-^.
plz mark it as brain liest...
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