solve this x^4+3x^2y^2+4y^4
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Answer:
Answer:
x=2 and y=2
Step-by-step explanation:
Let's solve your system by substitution.
x+y=4;3x−2y=2
Step: Solvex+y=4for x:
x+y=4
x+y+−y=4+−y(Add -y to both sides)
x=−y+4
Step: Substitute−y+4forxin3x−2y=2:
3x−2y=2
3(−y+4)−2y=2
−5y+12=2(Simplify both sides of the equation)
−5y+12+−12=2+−12(Add -12 to both sides)
−5y=−10
−5y
−5
=
−10
−5
(Divide both sides by -5)
y=2
Step: Substitute2foryinx=−y+4:
x=−y+4
x=−2+4
x=2(Simplify both sides of the equation)
Answer:
x=2 and y=2
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