Question

solve this (x+y)(x-y)
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Answer 1

Answer:

(x+y)(x−y)=x²+yx−xy−y²=x²−y²

Step-by-step explanation:

The brackets in this case are redundant:

(x+y) + (x-y) = x + y + x - y = 2x

But this may not be the question you meant to ask.

Were you perhaps thinking of (x + y) (x - y) ?

This is a very important identity, which resolves as follows:

(x+y)(x−y)=x2+yx−xy−y2=x2−y2(x+y)(x−y)=x2+yx−xy−y2=x2−y2

This is known as the ‘difference of two squares’. Whenever you see (x + y) (x - y), you know that it means x2−y2x2−y2

This means that anything - 1 becomes an easy to resolve problem, because 1 is the square of itself.

So, 999999 can easily be factored as 1001 * 999, on the grounds that it is 1000000–1, and is therefore (1000 + 1) * (1000 - 1).

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Answer 2

(x+y)(x-y) = x2 - y2

as, x(x-y) + x(x-y)

= x2 -xy+xy -y2

= x2 - y2