Solve this
x2+4x+5=0
Anonymous:
bro is it -5??
Answers
Answered by
105
Hey user here is your answer.......
---->To find- x
-----> Given equation- x^2+4x+5=0
◆By quadratic formula
◆x^2+4x+5
◆D=b^2-4ac
◆D=(4)^2-4(1)(5)
◆=16-20
◆D=-4
So it is less than 4 so no real root exist in given equation
Thanks☺️
#Rohan
---->To find- x
-----> Given equation- x^2+4x+5=0
◆By quadratic formula
◆x^2+4x+5
◆D=b^2-4ac
◆D=(4)^2-4(1)(5)
◆=16-20
◆D=-4
So it is less than 4 so no real root exist in given equation
Thanks☺️
#Rohan
Answered by
0
Answer:
No factors.
Step-by-step explanation:
Factoring x2+4x+5
The first term is, x2 its coefficient is 1 .
The middle term is, +4x its coefficient is 4 .
The last term, "the constant", is +5
1 : Multiply the coefficient of the first term by the constant 1 • 5 = 5
2 : Find two factors of 5 whose sum equals the coefficient of the middle term, which is 4 .
-5 + -1 = -6
-1+ -5 = -6
1 + 5 = 6
5 + 1= 6
No two such factors can be found.
#SPJ3
Q1.Define quadratic equations
https://brainly.in/question/19169616
Q2.How to solve a quadratic equation
https://brainly.in/question/3878568
Similar questions