Question

Solve this
x2+4x+5=0 by using formula

Answer 1

Answer:

x^+ 5x - 1x + 5= 0

x (x + 5) - 1 (x + 5) = 0

( x - 1) ( x + 5) = 0

either x- 1 =0 ; x = 1

or x + 5 = 0 ; x = - 5

Answer 2

by quadratic formula

X2+4x+5=0

D=b^2 -4ac

D= 16-20

D=-4

-4 <.0 no real roots

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